Y=(10X-4)^1/2

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Solution for Y=(10X-4)^1/2 equation: 


x in (-oo:+oo)

Y = ((10*X-4)^1)/2 // - ((10*X-4)^1)/2

Y-(((10*X-4)^1)/2) = 0

Y-((10*X-4)/2) = 0

(-1*(10*X-4))/2+Y = 0

(-1*(10*X-4))/2+(2*Y)/2 = 0

2*Y-1*(10*X-4) = 0

2*Y-10*X+4 = 0

(2*Y-10*X+4)/2 = 0

(2*Y-10*X+4)/2 = 0 // * 2

2*Y-10*X+4 = 0

x belongs to the empty set

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